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                                                                       y
                                                                     20
                                                                                   x
                                                                   -1       2

                                                                   -20


                                                                   FIGURE 4.32
                                                                    3
                                                                         2
                                                                y = 2x − 3x − 12x + 5
                                     Thus, f has two critical numbers, x =−1 and x = 2. Notice from the graph in
                                     Figure 4.32 that these correspond to the locations of a local maximum and a local
                    y
                                     minimum, respectively.


                   4                 EXAMPLE 3.7     An Extremum at a Point Where the
                                                     Derivative Is Undefined

                                     Find the critical numbers and local extrema of f(x) = (3x + 1) 2∕3 .
                                     Solution Here, we have
                                 x
              -2          2                                    2                   2
                                                         ′
                                                        f (x) =  (3x + 1) −1∕3 (3) =    .
                FIGURE 4.33                                    3               (3x + 1) 1∕3
                y = (3x + 1) 2∕3               ′                 ′                     1
                                     Of course, f (x) ≠ 0 for all x, but f (x) is undefined at x =− . Be sure to note that
                                                                                       3
                                       1
                                                                     1
                                     − is in the domain of f. Thus, x =− is the only critical number of f. From the
                                       3
                                                                     3
                                     graph in Figure 4.33, we see that this corresponds to the location of a local
                                     minimum (also the absolute minimum). If you use your graphing utility to try to
                                     produce a graph of y = f(x), you may get only half of the graph displayed in Figure
         REMARK 3.2                  4.33. The reason is that the algorithms used by most calculators and many
                                     computers will return a complex number (or an error) when asked to compute
           Fermat’s Theorem says that  certain fractional powers of negative numbers. While this annoying shortcoming
           local extrema can occur only  presents only occasional difficulties, we mention this here only so that you are
           at critical numbers. This does  aware that technology has limitations.
           not say that there is a local
           extremum at every critical
           number. In fact, this is false, as  EXAMPLE 3.8  A Horizontal Tangent at a Point That Is Not
           we illustrate in examples 3.8             a Local Extremum
           and 3.9.
                                                                                   3
                                     Find the critical numbers and local extrema of f(x) = x .
                                     Solution It should be clear from Figure 4.34 that f has no local extrema. However,
                                      ′
                                             2
                                     f (x) = 3x = 0 for x = 0 (the only critical number of f). In this case, f has a horizontal
                                     tangent line at x = 0, but does not have a local extremum there.
                    y
                                     EXAMPLE 3.9      A Vertical Tangent at a Point That Is Not
                   2                                 a Local Extremum

                                     Find the critical numbers and local extrema of f(x) = x 1∕3 .
                                x
             -2           2
                                     Solution As in example 3.8, f has no local extrema. (See Figure 4.35 on the follow-
                                                    ′
                                                          1 −2∕3
                  -2                 ing page.) Here, f (x) = x  and so, f has a critical number at x = 0. (In this case,
                                                          3
                                     the derivative is undefined at x = 0.) However, f does not have a local extremum
                                     at x = 0.
                FIGURE 4.34                                                                                         Copyright © McGraw-Hill Education
                   y = x 3               You should always check that a given value is in the domain of the function before
                                     declaring it a critical number, as in example 3.10.


        254 | Lesson 4-3 | Maximum and Minimum Values
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