Page 37 - E-LKPD KESETIMBANGAN KIMIA

[NH ] 2 (PNH ) 2
3
3
K = [N ][H ] 3 K = (PN )(H ) 3
c
p
2
b. BiCl + H O 2 ⇄ BiOCl (s) + 2HCl (aq) 2 2
2 (l)
3 (aq)

[HCl] 2 (PCl) 2
K = K =
c
p
[BiCl ] (PBiCl )
3
3
c. 2H S + 3O 2 (g) ⇄ 2H O + 2SO 2(g)
2 (g)
2 (g)

2
2
[H O] [SO ] 2 (PO) (PSO ) 2
2
2
2
K = [H S] [O ] 3 K = (PH S) (O ) 3
c
p
2
2
2
2
2
2

2. 2 2( ) ⇄ 2 ( ) + 2( )

Mula 5 mol - -
2
Reaksi 2 mol 2 mol 1 mol
Setimbang 3 mol 2 mol 1 mol

Karena volume wadah 2 liter, maka harga konsentrasi sama dengan mol/volume.
3 mol
[NO ] = = 1,5 M
2
2 l
2 mol
[NO] = = 1 M
2 l
1 mol
[O ] = = 0,5 M
2
2 l

Sehingga,
2
2
[NO] [O ] [1] [0,5] 0,5
2
K = = = = 2,2 X 10
-1
c
[NO ] 2 [1,5] 2 2,25
2

3. 2 3( ) ⇄ 2 2( ) + 2( )

2
Kp = (P SO 2 ) (P O 2 )
2
) Maka:
(P SO 3
2
P total = 10 atm, maka: (P SO 2 ) (P O 2 )
Kp = 2
P SO = mol SO 2 × total (P SO 3 )
 2 mol total (6) (2)
2
0,3 mol Kp = atm
P SO = × 10 atm (2) 2
2
0,5 mol 72
P SO = 6 atm Kp = 4 atm
2
Kp = 18 atm

 P O = mol 2 × total
2
mol total
0,1 mol
PO = × 10 atm
2
0,5 mol
P O = 2 atm
2

 P SO = mol 3 × total
3
mol total