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9.2 Expanding brackets



               9.2 Expanding brackets


               Some algebraic expressions include brackets.
               To expand a term with brackets, you multiply each term inside the   4(n + 3) means 4 × (n + 3), but you
                                                                                  usually write an expression like this
               brackets by the term outside the brackets. Expanding a term with   without the multiplication sign.
               brackets is sometimes called expanding the brackets or multiplying
               out the brackets.



               Worked example 9.2

                Expand the brackets.
                a  4(n + 3)      b  2(x − 5)     c  3(2g + h)

                a  4(n + 3)  = 4 × n + 4 × 3     Multiply the 4 by the n then the 4 by the 3.
                            = 4n + 12            Simplify the 4 × n to 4n and the 4 × 3 to 12.
                b  2(x − 5)  = 2 × x − 2 × 5     This time there is a minus sign before the 5,
                            = 2x − 10            so you need to take away the 10 from the 2x.
                c  3(2g + h) = 3 × 2g + 3 × h    The fi rst term is 3 × 2g, which is the same as 3 × 2 × g
                            = 6g + 3h            which simplifi es to 6g.

               )     Exercise 9.2


               1  Expand the brackets.
                  a  2(x + 5)      b  3(y + 6)      c  4(w + 2)      d  5(z + 5)
                  e  3(b − 1)      f  7(c − 4)      g  6(d − 9)      h  2(e − 8)
                  i  6(2 + f )     j  2(1 + g)      k  5(7 + h)      l  9(3 + i)
                  m 6(2 − x)       n  2(1 − y)      o  5(7 − p)      p  9(3 − q)

               2  Multiply out the brackets.
                  a  3(2x + 1)     b  4(3y + 5)     c  5(2w + 3)     d  6(4z + 7)
                  e  2(3b − 4)     f  4(2c − 3)     g  6(5d − 1)     h  8(3e − 6)
                  i  3(1 + 2f )    j  5(3 + 4g)     k  7(6 + 7h)     l  9(5 + 4i)
                  m 8(3 − 5x)      n  12(2 − 3y)    o  6(5 − 8p)     p  2(13 − 4q)
               3   This is part of Bethan’s homework.
                  Bethan has made a mistake on             Question      Multiply out the brackets.
                  every question.                          a   4(x + 4)             b   2(6x – 3)
                  Explain what Bethan has done             c   3(2 – 5x)            d   6(2 – x)
                  wrong.                                   Solution
                                                           a   4(x + 4) = 4x + 8    b   2(6x – 3) = 12x – 3
               4   Which one of these expressions is
                  different from the others?               c   3(2 – 5x) = 6 + 15x  d   6(2 – x) = 12 – 6x = 6x
                 Explain your answer.


                    2(12x + 15)      6(5 + 4x)
                    3(10 + 8x)      4(6x + 26)






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