Page 7 - Bahan Ajar Berbasis Flipped Learning pada materi Diferensial
P. 7
( + h) − ( )
′( ) = lim
h→0 h
3
2
+ 3 ℎ+3 ℎ + ℎ + 9 − ( + 9)
3
2
3
= lim
h→0 h
3 ℎ+3 ℎ + ℎ 3
2
2
= lim
h→0 h
ℎ(3 + 3 ℎ + ℎ )
2
2
= lim
h→0 h
= lim(3 + 3 ℎ + ℎ )
2
2
h→0
2
2
= 3 + 3 . 0 + 0
2
= 3 + 0 + 0
= 3
2
3
d. ( ) =
( + ℎ) = 3
+ ℎ
( + h) − ( )
′( ) = lim
h→0 h
3 3
+ ℎ −
= lim
h→0 h
3 − 3( + ℎ)
( + ℎ)
= lim
h→0 h
3 − 3 − 3ℎ
= lim
h→0 ℎ ( + ℎ)
−3ℎ
= lim
h→0 ℎ ( + ℎ)
−3
= lim
h→0 ( + ℎ)
−3
= lim
2
h→0 + ℎ
6 | T u r u n a n K e l a s X I S M A
