Page 41 - Kalkulus Lanjut

1 2 1 2 1 1
2
1. ∫ ∫ = ∫ (∫ ) = ∫ ( ) = ∫ (2 − 1) = 1
0 1 0 1 0 1 0

4
4
2
2
2
2
2. ∫ ∫ ( + ) = ∫ (∫ ( + ) )
2
2
2 1 2 1

4 1 2
= ∫ ( + )
3
2
2 3 1
7
4
= ∫ ( + 3 )
2
2 3
4


 7 y + y 3 
=
 3 2 
 7

=

 2
 4 + 4 3  −  7 + 2 3 
 3 2   3 
= 60 3

4 2 4  2 
2
2
3.   ( xy + 3 y ) dydx =   xy + 3 y ) dy dx

 (
2 1 2  1 
4  xy 2 3  2


=  + y  dx
2  2 1 
4 2
4  x 2 . 2   x 1 . 2   x 3 

=  + 2 3  −  +1 3  dx =   2 + 7 dx





2  2   2  2 1
4
=  3 2 + 7  x 
 x
4
  2
(12 += 28 ) ( +− 3 14 )

= 23

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