Page 7 - Actividad No. 1, Segunda Parte ER
P. 7

Introducción a las tecnologías para el control y la



                                                      automatización de procesos empresariales sostenibles
                                                                                Ing. Alberto Tama Franco, MSc.



                                                       3         1          2
                                           H   ( ) s =    +             −
                                             1
                                                      2s      ( 2 s +  ) 2  s +  1

                                              ( 3 s + 1 )(s +  ) 2 +  ( s s +  ) 1 − 4s (s +  ) 2
                                 H   ( ) s =
                                   1
                                                         2s (s +  1 )(s +   ) 2

                                                (
                                                               )
                                              3 s +    3s +  2 +   s + −     4s −   8s
                                                                    2
                                                   2
                                                                                2
                                                                         s
                                   H  1 ( ) s =
                                                         2s (s +  1 )(s +   ) 2

                                    3s +   9s + +      2   s    4s −   8s           2s +  6
                                                 6 s + −
                                       2
                                                                   2
                         H 1 ( ) s =                                       =
                                             2s (s +  1 )(s +   ) 2           2s (s + 1 )(s +   ) 2

                                           2s +  6                                   s +  3
                          H   ( ) s =                              H  ( ) s =
                            1
                                     2s (s +  1 )(s +   ) 2          1          ( s s + 1 )(s +  ) 2


                                                1                                 ( s s +  20 )
                             H  2 ( ) s =                          H 2 ( ) s =  2
                                        1+        5                            s +  20s +   5
                                               ( s s +  20 )


                                                  5                         s +  2  20s +  5
                                           s
                               H  3 ( ) s = +  s +  20          H 3 ( ) s =    s +  20



                                                                            ( )
                                                                   ( )
                                           H  eq ( ) s =  H 1 ( ) s H s H s
                                                                          3
                                                                  2

                                              s + 3            s (s +  20 )      s +  2  20s +  5
                          H    ( ) s =                                       
                             eq        s (s +  1 )(s +   ) 2  s +  2  20s +  5      s +  20



                                                        s +  3             s +  3
                                      H    ( ) s =                  =
                                         eq
                                                                        2
                                                   (s + 1 )(s +   ) 2  s +   3s +  2
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