Page 50 - Phytochemistry -1 (PG404) / Clinical Pharmacy 2nd level students ( 2019 )
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Clinical pharmacy PharmD program             Third level                        Phytochemistry-1 (PG-504)


                   5- Pipette 10 ml of the filtrate into a 250 m1 round bottorn flask (or conical

                       flask). Adjust the pH of the solution to 7-8 with few drops of 5%w/v
                       solution of Na 2CO 3. Add a mixture of 8m1 FeCL 3 and 12 ml water
                       and mix.
                   6- Heat on a boiling water bath under reflux for 20 minutes. Add 1 ml

                       Conc. HCL to render acidic and continue reflux for further 20 minutes,
                       shaking frequently until a precipitate is dissolved.
                   7- Cool, transfer and extract with 3 portions each of 25 ml of ether, passing

                       each fraction over anhydrous Na 2SO 4 (about 5 g.) placed in a small
                       funnel,  receiving  the  ether  extract  into  a  100  ml  volumetric  flask,
                       complete to volume with ether.

                   8- Pipette 10 ml of the etherial extract into a beaker, evaporate just to
                       dryness on a water bath and dissolve the residue in 10 ml 1N KOH
                       accurately measured, filter in case of any turbidity.

                   9- Without delay, measure the absorbance of the color of the resulting
                       solution at 500 nm using 1 cm cuvette.
                   10-  Determine  the  content  of  total  combined  anthraquinones  in  senna

                       calculated as sennoside. A or B taking ''200" as the value-of E(1%,
                       1cm).
                   Each 1 mg of Rhein is equivalent to 1.8 mg of sennoside A or B.

                   Calculation:
                   Sennoside content of each tablet



                                     Absorbance A        100      100      100
                                  =                                                 1.8
                                           200            10       10       2
                                                         1.8    100
                                                =                       
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