Page 1033 - Basic Electrical Engineering

= 1.414 × 28.27

i.e., V = 40 V
m
PIV = V = 40 V
m

Example 15.2 A half-wave rectifier produces a maximum load current (peak

value) of 50 mA through a 1200 Ω resistor. Calculate the PIV of the diode.
The diode is of silicon material.

Solution:

Assuming a voltage drop of 0.7 V across the silicon diode, the peak value of
current, I is
m

I is given as 40 mA.
m

Therefore,

or,

−3
V − 0.7 = 1200 × 40 × 10 = 48V
m