Page 335 - Basic Electrical Engineering

Taking the cosine and sine components of the branch currents and the line
current

I cos ϕ = I cos ϕ + I cos ϕ 2
2
1
1
and I sin ϕ = I sin ϕ + I sin ϕ 2
1
2
Substituting values

I cosϕ = 15.41 × 0.942 + 11.15 × 0.335 = 18.24

I sinϕ = 15.41 × 0.325 + 11.15 × 0.485 = 10.4

Current, I can also be calculated as

I = VY

where Y = Y + Y 2
1

Example 3.10 In Fig. 3.35 is shown a parallel circuit, an inductance L and
a parallel R connected across 200 V, 50 Hz ac supply. Calculate:

(a) the current drawn from the supply; (b) apparent power; (c) real power; (d)

reactive power.