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Calender                                                                                            253
                In our example, m = 4.
            •  D is the last two digits of the year, D = 13.
            •  C stands for century: it’s the first two digits of the year. In our case, C = 20.
            Now let’s substitute our example numbers into the formula.
                                           D
                                                C
                            13×   −m  1      
                                                     2 C
                      f  = +    5     + D +    +   −×  .
                        k
                                               
                                          
                                                 4 
                                           4 
                               ×−
                              13 4 1       13    20
                                                      2 20.
                     f  =  25 +      + 13 +      +      −×
                               5           4     4 
                              51
                       = f  +25         5  +  + 13  [3.25 ] [ ] − 5  40.
                                           +
            F = 25 + 10 + 13 + 3 + 5 – 40 = 16
            Now divide this value of f = 16 by 7 remainder is 2.
            A remainder of 0 corresponds to Sunday, 1 means Monday, etc
            Here remainder 2 means Tuesday.
            In this formula we may get value of f as negative if this is the case then we will add multiple of 7 to make it positive
            e.g if f = – 17 then f = – 17 + 3 × 7 = 4 so f = – 17 is same as that of 4.
            Method 2: The Key Value Method:
            In this method we have to memorize few codes but this method is quick and fast in calculation. We’ll take an example
            of December 20, 1984 as an example.
            •  Take the last 2 digits of the year. In this case it is 84.
            •  Divide it by 4, and find quotient, since [84/4] = 21
            •  Add the day of the month. In our example, 20 + 20 = 40.
            •  Add the month’s key value, from the following table.
                      Jan    Feb    Mar     Apr    May    June    July   Aug    Sept    Oct    Nov     Dec
                       1      4       4      0      2       5      0      3       6      1       4      6
            •  The month for our example is December, with a key value of 6. Hence 40 + 6 = 46.
            •  If month is January or February of a leap year, subtract 1. We’re using December, so it is not applicable here.
            •  Add the century code from the following table.

                                               1700s     1800s    1900s    2000s
                                                  4        2        0        6
            •  Our example year is 1984, and the and get the code 6. Now we add this to our running total: 42 + 6 = 48.
            •  Add the last two digits of the year. 48 + 82 = 130.
            •  Divide by 7 and take the remainder. This time, 1 means Sunday, 2 means Monday, and so on. A remainder of
               0 means Saturday. 130 / 7 = 18, remainder 4, so December 16, 2482 will be on the fourth day of the week--
               Wednesday.

            SOME MORE INTERESTING POINTS:

            A month has either 28 (Non leap year February), 29 (Leap year February), 30 or 31 days.
            If a month start with Monday, Tuesday, or Wednesday the month will have 4 Saturdays and 4 Sundays i.e total 8
            weekends.
            If a month start with Thursday the month will have 5 Saturdays and 4 Sundays i.e total 9 weekends.

            If a month start with Friday the month will have 5 Saturdays and 4 Sundays i.e total 9 weekends if month has 28, 29
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