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Cubes                                                                                               249
                But here we have removed a cubes of the form of   29.  (a) From top face (out of 3 × 3 square face) only one
                3  ×  3  × 3  and again put it back  so  out of three   cube is with one face painted.
                new exposed faces of big cube we will have 4 cubes      From 4 vertical faces each face will give us 6 cubes
                in each face that is painted with one colour hence    hence total number of cubes from vertical faces is
                number of cubes from these three surfaces is 3 × 4    6 × 4 = 24.
                = 12                                                  From bottom face we will get 3 × 3 = 9 cubes
                Now consider out of 3 × 3 × 3 cubes we will have 6
                cubes (one in each face) which are painted only one      So total number of cubes with one face painted is 1
                face.                                                 + 24 + 9 = 34
                Hence total number of cubes = 48 + 12 + 6 = 66   30.  (d) Number of cubes with no face painted is
            23.  (a) Without any changes number of cubes with no       105 – 34 – 24 – 20 = 27
                                           3
                face colour is given by (6 – 2)  = 64                 Or else all the 3 × 3 × 3 inner cubes will remain
                Now because of removal of 3 × 3 × 3 cubes from        coloured.
                one of the corner from each face that were not   Solution for 31–35:
                painted earlier got exposed and will get painted, so   Here we have following cases:
                from 3 × 3 × 3 cubes 4 × 3 = 12 cubes got painted,   Case (i): When same colour is on opposite face.
                and a similar number from 3 exposed faces of big
                cube got painted.                                Case (ii): When two red colours are on opposite face and
                Total number of cubes with no face painted is    blue & green on adjacent faces
                64 – 12 – 12 = 40                                Case (iii): When two green colours are on opposite face
            24.  (c) Out of 27 small cubes from 3 × 3 × 3, outer 26   and blue &red on adjacent faces.
                           st
                cubes are 1  painted with blue and then it is kept   Case (iv): When two blue colours are on opposite face
                back with original cube and painted with yellow so   and red & green on adjacent faces.
                out of 26 cubes only 5 edges will give us cubes with   Case (v): When same colours are on adjacent faces.
                both the colours and number of such cubes are 12  31.  (a) We will evaluate  the value  of ‘K’ in each  and
            25.  (d) Out of 12 cubes in previous question there are   every case:
                4 cubes with 2 faces yellow so number  of cubes       Case (i): In this case number of cubes is given by 4
                painted two faces only one with yellow and one with   common edges except all 8 corner ones so number
                blue is 12 – 4 = 8                                    of cubes is 5 × 4 = 20
            Solution for 26–30:                                       Case (ii): In this case number of cubes is given by 4
            26.  (d) Number of cubes removed from top face = 16       common edges (From one edge we will get 5 cubes
                Number of cubes removed from bottom face = 4          with 2 face painted) except 6 corner ones (2 corner
                Number of cubes left = 125 – (16 + 4) = 105           cubes are painted with only red and blue) so number
            27.  (a) Number of cubes with three coloured face on the   of cubes is 5 × 4 + 2 = 22
                top side = 4                                          Case (iii): In this case number of cubes is given by 2
                                                             nd
                Number of cubes with three coloured face on the 2     common edges (From one edge we will get 5 cubes
                from top side = 4                                     with 2 face painted) so number of cubes is 5 × 2 =
                Number  of cubes with three  coloured  face on  the   10.
                bottom side = 12                                      Case (iv): In this case number of cubes is given by 4
                Total number of such cubes = 12 + 8 = 20              common edges (From one edge we will get 5 cubes
            28.  (b) Number of cubes with two face painted from the   with 2 face painted) except 6 corner ones (2 corner
                top side (Which is a square of 3 × 3 = 9 cubes) is 4.  cubes are painted with only red and blue) so number
                                                             nd
                Number of cubes with two face painted from the 2      of cubes is 5 × 4 + 2 = 22
                from top side (Which has four edges and each edge      Case (v): In this case number of cubes is given by 3
                has 3 such cubes) is 4 × 3 = 12.                      common edges (From one edge we will get 5 cubes
                Number of such cubes from vertical edges is 4 × 1 = 4  with 2 face painted) except 6 corner ones (2 corner
                                                                      cubes are painted with only red and blue) so number
                Number of such cubes from bottom face is 4 × 1 = 4    of cubes is 5 × 3 + 2 = 17
                Hence total such cubes is 4 + 12 + 4 + 4 = 24         Hence option (A) gives the all possible value of ‘K’
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