Page 266 - Services Selection Board (SSB) Interviews

262 Calender
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in that case 1 January must be either Friday or hence 1 January will be either Sunday (For non
Saturday leap year) or Saturday (For leap year) then January
4. (d) If November month has 5 Mondays then dates will have 9 or 10 weekends.
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must be 1 , 8 , 15 , 22 , and 29 or second Case (ii) If a month start with Sunday the month will
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group of dates must be 2 , 9 , 16 , 23 , and 30 th have 4 Saturdays and 5 Sundays i.e total 9 weekends.
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Now lets find out the number of days or odd days In this case 31 December will be Wednesday hence
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between 1 April till 1 November 1 January will be either Wednesday (For non leap
Number of days in April: 29 or number of odd year) or Tuesday (For leap year) then January will
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days are 1 (here we have not included 1 April so have 8 or 9 weekends.
number of days is 30 – 1 = 29) Hence number of weekends in January will be 8 or
Number of days in May: 31 or number of odd 9 or 10.
days 3 6. (c) If there are 53 Saturday and Sunday that means
Number of days in June: 30 or number of odd year is a leap year and last day of year is Sunday so
days 2 1 day of January must be Saturday then January
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Number of days in July: 31 or number of odd will have 10 weekends.
days :- 3 7. (a) In a period of 100 years there are 23 or 24 leap
Number of days in August: 31 or number of odd years (as for century year it might be or might not be
days 3 a leap year, as 1900 was not a leap year)
Number of days in September: 30 or number of Number of odd days in a period of 100 years is 100
odd days 2 + 23 or 100 + 24 or 123/124 odd days,
Number of days in October: 31 or number of Number of odd days in 100 years is when 123/124
odd days 3 divided by 7, remainder is 4 or 5. So next century
Number of days in November: 1 or number of should start with Monday or Tuesday.
odd days 1 8. (b) In a period of 100 years there are 23 or 24 leap

So total number of odd days are 1 + 3 + 2 + 3 years (as for century year it might be or might not be
+ 3 + 2 + 3 + 1 = 18, when divided by 7 gives a leap year, as 1900 was not a leap year)
remainder 4 Number of odd days in a period of 100 years is 100
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Hence 1 April must be 4 days back from + 23 or 100 + 24 or 123/124 odd days,
Monday i.e Thursday. Then weekend will Number of odd days in 100 years is when 123/124
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be 3 , 4 , 10 11 , 17 , 18 , 24 , 25 , divided by 7, remainder is 4 or 5. So next century
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And if 2 November is Monday then 1 April must should start with Friday or Saturday.
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be Friday. Then weekend will be 2 ,3 , 9 ,10 , 9. (a) Last day of century can be Friday, Wednesday,
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16 ,17 , 23 , 24 and 30 total 9 weekends Monday, or Sunday and it repeats the cycle. So
Hence number of weekends may be 8 or 9 1 day of next century must be either Saturday,
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5. (d) Here we have two cases: Thursday, Tuesday, or Monday and so it must not be
Case (i): If a month start with Thursday the month Wednesday, Friday, & Sunday
will have 5 Saturdays and 4 Sundays i.e total 9 10. (a) If previous year is leap year then calendar of May
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weekends. In this case 31 December will be Sunday is similar to July