Page 286 - Services Selection Board (SSB) Interviews

282 Games and Tournament
Since total number of goals scored and goals against is same hence we can find goals against Marconi which is (11 +
9 + 5 + 1 + 7 + 4) – (5 + 9 + 7 + 4 + 5) = 37 – 30 = 7. Since Bose sadan scored 11 goals while goals against is 5
it is possible when all the matches are won with (3-1) (4-2) and (4-2)
Since Marconi got 4 points which is possible with 1 win (3 points) 1 draw (1 point) and 1 loss (0 point)
Similarly Rankin got 3 points and also Goals for is 4 and against is 5 so all three matches can not end with draw
(It is when goals for is equal to goals against) so 3 points is possible with 1 win and 2 loss.
Faraday scored only 1 goal, goal against is 4 and won 1 match it is possible only when he won by (1-0) and lost two
matches with (0-2) each[ as with the combination (0-1) and (0-3) is not possible since (0-3) goal difference is 3]
Since Edison won on Wednesday with (2-0) and total goals for is 5 while against is 7, so in other two game it lost with
(2-4) and (1-3)
Draw is casued only with Diesel and Marconi hence they must have played with each other and the match was tie.
On Monday Diesel played with Bose, on Tuesday Diesel played with Edison while on Wednesday Diesel played with
Marconi.
On Wednesday Bose must have played with Marconi
Faraday played against Edison on Wednesday and lost with (0-2)
Marconi played against Faraday on Monday while against Bose on Tuesday.
Since Rankin scored 4 goals and conceded 5 goals result of Bose and Rankin (3-1) similarly result of Rankin and Edison
(3 – 1)
Now we can conclude that Bose sadan won against Diesel and Marconi with (4-2) and (4-2)
Diesel won against Edison with (4-2)
So matches on Monday:,
So final result

Monday Bose and Diesel (4-2) Marconi and Faraday (2-0) Edison and Rankin (1-3)
Tuesday Bose and Marconi (4-2) Diesel and Edison (4-2) Faraday and Rankin (1-0)
Wednesday Bose and Rankin (3-1) Diesel and Marconi (3-3) Edison and Faraday (2-0)

Number of points are as follows: Bose (3 + 3 + 3 = 9), Diesel (0 + 3 + 1 = 4), Edison (0 + 0 + 3 = 3), Faraday (0
+ 3 + 0 = 3), Marconi (3 + 0 + 1 = 4), and Rankin (3 + 0 + 0 = 3)
38. (b) Total number of matches is 9, out these 9 matches, the matches that end with goal difference of 2 is Monday:
all the three matches, Tuesday 2 matches and Wednesday 2 matches so required percentage is 7 × 100/9 = 77.77%
39. (c) Out of 9 matches only 1 match end up with tie so total number of points is 8 × 3 + 2 = 26
40. (a) From the table Diesel team won against Edison.
41. (d) Since total number of points is 26 so number of points more than 2.6 but less than 5.2 is (i.e points 3. 4, 5) 5.
42. (b) The new condition would be:

Monday Bose and Diesel (2-4) Marconi and Faraday (0-2) Edison and Rankin (3-1)
Tuesday Bose and Marconi (2-4) Diesel and Edison (2-4) Faraday and Rankin (0-1)
Wednesday Bose and Rankin (1-3) Diesel and Marconi (3-3) Edison and Faraday (0-2)
Initially total number of goals made by the teams are Bose (11), Diesel (9), Edison ( = 5), Faraday ( = 1), Marconi
( = 7), and Rankin ( = 4)
Now total number of goals made by the teams are Bose (5), Diesel (9), Edison (7), Faraday (4), Marconi (7), and
Rankin (5)
So only Diesel and Marconi have the same number of goals.