Page 184 - FUNDAMENTALS OF COMPUTER
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                     184                         Fundamentals of Computers                          NPP

                        Now, See the circuit below                  gmW hr {ZåZ n[anW H$mo ^r XoImo…


                                                A
                                                                             A + B
                                               B

                        Above circuit can be drawn as:              Cnamoº$ n[anW H$mo {ZåZmZwgma ~Zm gH$Vo h¢ …


                                                  A
                                                  B                       A + B


                         Problem 3.37                                àíZ 3.37
                        Implement using NAND Gates:                 {ZåZ g_rH$aU hoVw NAND JoQ> H$s ghm`Vm go
                                                                n[anW ~ZmAmo…


                                                          Y =  A .  B
                    Solution:                                   hc:
                        First we draw the Basic Gate implemen-      gd©àW_ ~o{gH$ JoQ>m| H$s ghm`Vm go n[anW ~ZmZo
                    tation:                                     na:


                                                 A
                                                                            A.B
                                                 B
                                                             B
                        To convert AND Gate into  NAND Gate,        AND JoQ> H$mo  NAND  _| n[ad{V©V  H$aZo hoVw
                    put a bubble at the output. And to cancel this  AmCQ>nwQ> _| EH$ ~~b bJmZm hmoVm h¡ naÝVw Bg ~~b
                    bubble put a NOT Gate in series:            H$m à^md Xya H$aZo hoVw EH$ NOT JoQ> ^r bJmZm n‹S>oJm…
                                                 A
                                                                             A.B
                                                 B
                        Now only two NOT Gates are remaining.       {g’©$ Xmo NOT JoQ> ~Mo h¢& A~ XmoZm| NOT JoQ>m| H$mo
                    But as we know that NOT Gate is equivalent to  em°Q>}S> NAND JoQ> H$s ghm`Vm go ~ZmZo na…
                    Shorted NAND Gate, therefore replace them
                    with shorted NAND.

                                          A

                                          B                                         A.B
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