Page 186 - FUNDAMENTALS OF COMPUTER

NPP

186 Fundamentals of Computers NPP

Solution: hc:
F = A.B + C
Basic Gate implementation is: Cnamoº$ \$bZ hoVw _yb^yV JoQ>m| H$m n[anW Bg
àH$ma hmoJm:

A

B F
C
First Convert AND into NAND: gd©àW_ AND JoQ> H$mo NAND JoQ> _| n[ad{V©V
H$aZo na:

A

B
C F

Convert OR into Bubbled OR: OR JoQ> H$mo ~~ëS> OR JoQ> _| n[ad{V©V H$aZo na:
A

B

C F

The Bubbled OR is equivalent to NAND. ~~ëS> OR Ho$ ñWmZ na NAND VWm NOT Ho$
The NOT Gate is equivalent to shorted NAND: ñWmZ na em°Q>}S> NAND ~ZmZo na…

A

B
F
C

Problem 3.40 àíZ 3.40
Perform NOR-NOR implementation of {ZåZ \$bZ hoVw NOR-NOR `wº$ n[anW ~ZmBE…
the following Boolean function:
F = A.B + C
Solution: hc:

Basic Gate implementation is _yb^yV JoQ> `wº$ n[anW Bg àH$ma h¢…