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NPP Number System, Boolean Algebra and Logic Circuits 191
Convert two NOT Gates and one bubbled XmoZm| NOT JoQ>m| H$mo em°Q>}S> NAND VWm ~~ëS>
OR Gate into NAND Gates: OR H$mo NAND _| ~XbZo na…
A
B
Problem 3.46 àíZ 3.46
Draw XOR Gate using NOR Gates: XOR JoQ> H$mo NOR JoQ>m| H$s ghm`Vm go ~ZmAmo…
Solution:
The output expression can be written as: AmCQ>nwQ> g_rH$aU {ZåZ àH$ma go {bIm Om
gH$Vm h¡:
Y = (A+ B ) (A. + B )
Implement this equation using basic gates: Bg g_rH$aU H$mo _yc^yV JoQ>m| go ~ZmZo na:
A
B
Convert OR gates into NOR gates by A~ OR JoQ>m| H$mo NOR _| ~XbZo na; AND JoQ>
putting two bubbles, one at output of OR and ^r ~~ëS> AND JoQ> _| ~Xb OmEJm…
one at the input of AND.
The Circuit will look as shown below: g{H©$Q> {ZåZ àH$ma go {XIoJm…
A
B
Bubbled AND is equivalent to NOR. The ~~ëS> AND VWm NOT JoQ>m| H$mo NOR _| ~XbZo
two NOT Gates are equivalent to shorted NOR: na {ZåZ n[anW àmßV hmoJm…