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                  NPP               Number System, Boolean Algebra and Logic Circuits              191


                      Convert two NOT Gates and one bubbled       XmoZm|  NOT JoQ>m| H$mo em°Q>}S>  NAND VWm ~~ëS>
                  OR Gate into NAND Gates:                    OR H$mo NAND _| ~XbZo na…

                                        A

                                        B







                       Problem 3.46                                àíZ 3.46

                      Draw XOR Gate using NOR Gates:              XOR JoQ> H$mo NOR JoQ>m| H$s ghm`Vm go ~ZmAmo…
                  Solution:
                      The output expression can be written as:    AmCQ>nwQ>  g_rH$aU {ZåZ  àH$ma  go {bIm Om
                                                              gH$Vm h¡:
                                                    Y =  (A+ B ) (A.  + B )
                      Implement this equation using basic gates:  Bg g_rH$aU H$mo _yc^yV JoQ>m| go ~ZmZo na:

                                     A
                                     B







                      Convert OR gates  into NOR gates by         A~ OR JoQ>m| H$mo NOR _| ~XbZo na; AND JoQ>
                  putting two bubbles, one at output of OR and  ^r ~~ëS> AND JoQ> _| ~Xb OmEJm…
                  one at the input of AND.
                      The Circuit will look as shown below:       g{H©$Q> {ZåZ àH$ma go {XIoJm…
                                    A

                                    B








                      Bubbled AND is equivalent to NOR. The       ~~ëS> AND VWm NOT JoQ>m| H$mo NOR _| ~XbZo
                  two NOT Gates are equivalent to shorted NOR:  na {ZåZ n[anW àmßV hmoJm…
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