Page 25 - Kelas XII_Matematika Peminatan_KD 3.3

2. Kunci Jawaban Latihan Pembelajaran II

NO JAWABAN SKOR

1.a = ( ) =cos ( 4x -  )
Misalkan u = 4x -  → = cos 1
= 4 1

= − sin 1
= = − sin . (4)
.
1.b 1

= −4. sin
b.
= −4 cos(4x −  ) 1

5
5
y=f(x) = cos (3 – 2x)= (cos (3 − 2 ))

Misalkan: u = (3 − 2x) → = −2 1

v = cos u → = − sin 1

1
4
y = v → = 5.
5

4
.
.
= = 5 . (− sin ). (−2) 2

4
= 5. (cos ) . (− sin ). (−2)
1

4
= 5. (cos(3 − 2 )) . (− sin(3 − 2 )). (−2) 2

4
= 10 (3 − 2 )sin (3 − 2 )
2

3
2. ( ) = 4
1
3
′
( ) = 4.3. . (− sin ) 1
2
3
′
( ) = −12. sin . 1

3
′
( ) = −12. sin . 3 = −12. sin . (cos )
3 3 3 3 3
3
1
1
1

′
3
( ) = −12. √3 (. ) = -6 √3.( ) = − √3
3 2 2 8 4

2
3. ( ) = (2 + )
6
2
1
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