Page 183 - Mechatronics with Experiments
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MECHANISMS FOR MOTION TRANSMISSION  169
                             where T 12  is described by the orientation of the second coordinate frame and position
                             coordinates of its origin with respect to the first coordinate frame.

                                                         ⎡ e 11  e 12  e 13  x 1A ⎤
                                                          e 21  e 22  e 23  y 1A
                                                         ⎢                 ⎥
                                                    T 12  =  ⎢             ⎥                   (3.226)
                                                         ⎢ e   e   e    z  ⎥
                                                           31   32  33   1A
                                                         ⎢                 ⎥
                                                         ⎣ 0   0   0    1 ⎦
                                                         ⎡ 0.0  −1.00.0  −0.5 ⎤
                                                         ⎢                   ⎥
                                                          1.0   0.00.0     0.5
                                                       =  ⎢                  ⎥                 (3.227)
                                                         ⎢ 0.0  0.01.0     0.0 ⎥
                                                         ⎢                   ⎥
                                                         ⎣ 0    0    0     1 ⎦
                             Notice that the orientation portion of the matrix is the coefficients of the relationships
                             between the unit vectors,
                                                 ⃗ i = cos   ⋅ ⃗ e + cos   ⋅ ⃗ e + cos   ⋅ ⃗ e  (3.228)
                                                        11  1      12  2     13  3
                                                   = e ⋅ ⃗ e + e ⋅ ⃗ e + e ⋅ ⃗ e 3             (3.229)
                                                             12
                                                         1
                                                     11
                                                                     13
                                                                 2
                                                   = 0.0 ⋅ ⃗ e + (−1.0) ⋅ ⃗ e + 0.0 ⋅ ⃗ e      (3.230)
                                                         1         2       3
                                                 ⃗ j = cos   ⋅ ⃗ e + cos   ⋅ ⃗ e + cos   ⋅ ⃗ e  (3.231)
                                                        21  1      22  2     23  3
                                                   = e ⋅ ⃗ e + e ⋅ ⃗ e + e ⋅ ⃗ e 3             (3.232)
                                                                     23
                                                         1
                                                             22
                                                                 2
                                                     21
                                                   = 1.0 ⋅ ⃗ e + (0.0) ⋅ ⃗ e + (0.0) ⋅ ⃗ e 3   (3.233)
                                                         1
                                                                  2
                                                 ⃗ k = cos   ⋅ ⃗ e + cos   ⋅ ⃗ e + cos   ⋅ ⃗ e 3  (3.234)
                                                                   32
                                                                      2
                                                            1
                                                        31
                                                                             33
                                                   = e ⋅ ⃗ e + e ⋅ ⃗ e + e ⋅ ⃗ e               (3.235)
                                                     31  1   32  2   33  3
                                                   = (0.0) ⋅ ⃗ e + (0.0) ⋅ ⃗ e + (1.0) ⋅ ⃗ e   (3.236)
                                                          1        2        3
                             Hence,
                                                       r 1P  = T ⋅ r 2P                        (3.237)
                                                             12
                                                          = [−1.51.50.01 ] T                   (3.238)
                             Example     The purpose of this example is to illustrate graphically that the order of a
                             sequence of finite rotations is important. If we change the order of rotations, the final
                             orientation is different (Figure 3.19). In other words, T ⋅ T ≠ T ⋅ T .Let T represent a
                                                                             2
                                                                                 2
                                                                                           1
                                                                                     1
                                                                          1
                                                     ◦
                                                                                              ◦
                             rotation about the x-axis by 90 , and T represent a rotation about the y-axis by 90 . Figure
                                                            2
                             3.19 shows the sequence of both T followed by T and T followed by T . The resulting
                                                                      2
                                                                            2
                                                         1
                                                                                         1
                             final orientations are different since the order of rotations are different. Finite rotations are
                             not commutative. We can show this algebraically for this case.
                                                          ⎡ 1.0  0.00.00.0 ⎤
                                                          ⎢                 ⎥
                                                           0.0   0.01.00.0
                                                     T =  ⎢                 ⎥                  (3.239)
                                                      1
                                                          ⎢ 0.0  −1.00.00.0 ⎥
                                                          ⎢                 ⎥
                                                          ⎣0     0   0    1 ⎦
                                                          ⎡ 0.00.0  −1.00.0 ⎤
                                                           0.01.0    0.00.0
                                                          ⎢                 ⎥
                                                     T =  ⎢                 ⎥                  (3.240)
                                                      2
                                                          ⎢ 1.00.0   0.00.0 ⎥
                                                          ⎢                 ⎥
                                                          ⎣0   0     0    1 ⎦
                             Clearly, T ⋅ T ≠ T ⋅ T .
                                        2
                                     1
                                                1
                                             2
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