Page 274 - Mechatronics with Experiments
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                                   For the second case the measured voltage is
                                                     (         )(        )
                                                         R L        R in
                                               v out  =                    K amp s               (5.88)
                                                                                v
                                                       R + R out  R + R s
                                                                   in
                                                        L
                                                     (  100  )(   1 000 000  )
                                                   =                          ⋅ 1 ⋅ v s          (5.89)
                                                      100 + 1   1 000 000 + 100
                                                     ( 100  )( 1 000 000  )
                                                   =                  ⋅ v s                      (5.90)
                                                      101   1 000 100
                                                   = 0.990 ⋅ v                                   (5.91)
                                                            s
                                                   = 9.90 V                                      (5.92)
                              which shows an error of 1% of the correct value of the voltage. Notice that there are two
                              components to the error in the gain due to input and output loading, one due to the input
                              loading (K ) and and the other due to the output loading (K ),
                                      1
                                                                             2
                                                        v out  = K ⋅ K ⋅ K amp s                 (5.93)
                                                                         v
                                                               2
                                                                   1
                              where,
                                                              (        )
                                                                  R in
                                                          K =                                    (5.94)
                                                           1
                                                                R + R s
                                                                 in
                                                               1 000 000
                                                            =                                    (5.95)
                                                               1 000 100
                                                              (         )
                                                                   R L
                                                          K =                                    (5.96)
                                                           2
                                                                R + R out
                                                                 L
                                                               100
                                                            =                                    (5.97)
                                                               101
                              This example illustrates that in order to minimize the effect of loading errors, components
                              should have very large input impedance (ideally infinite), and very small output impendace
                              (ideally zero).
                       5.5 SEMICONDUCTOR ELECTRONIC DEVICES
                              Electronic systems include components made using semiconductor materials, such as
                              diodes, SCRs, transistors, and integrated circuits (ICs). Pictures of some common semicon-
                              ductor devices are shown in Figure 5.9. Because current flow is accomplished through the
                              flow of electrons in the solid crystal structure of semiconductor materials, components made
                              from semiconductor materials are also called solid-state devices. The difference between an
                              electrical and electronic system lies in whether solid-state components (diodes, transistors,
                              ICs) are used in the circuit or not.

                              5.5.1 Semiconductor Materials

                              Semiconductor materials are the group IV elements in the periodic table. The most com-
                              monly used semiconductor materials are silicon (Si) and germanium (Ge). Semiconductor
                              materials have an electrical conductivity property that is somewhere in between the conduc-
                              tors and insulators (non-conductors), hence the name semiconductors. A silicon atom has
                              14 electrons, and four of these electrons revolve in the outermost orbit around the nucleus
                              (Figure 5.10a). In its pure form, silicon is not much use as a semiconductor. The crystalline
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