Page 123 - Servo Motors and Industrial Control Theory -
P. 123

118                                       7  Electrohydraulic Servo Motors

                                       q: = K x −  C p                    (7.7)
                                                 p
                                            1
            where,

                                        d            d
                                  K: =    q    C : =   q
                                    1
                                        dx      p   dp
                                     p: = con  x: = con
            The reader must be aware that the lower case variables represent variation from an
            operating point. This has not been implemented in Eq. (7.6) because it is clear that
            the equation represents the absolute values of the flow rate.
              The pressure forces the piston to move according to the equation of motion of

                                      Ap: = Ms y +  Csy                   (7.8)
                                             2
            In Eq. (7.8), M is the total mass of moving parts of the jack, A is the cross sectional
            area of the piston, and C represents the viscous friction that the numerical values
            must be given by manufacturers. The reader must know that s is the Laplace Trans-
            form operator and is the same as differentiation with respect to time assuming that
            all the initial conditions are zero.
              On the other hand, the flow equation from the spool valve assuming that the oil
            is incompressible moves through the jack according to the equation,

                                       q: = Asy + C · p                   (7.9)
                                                 1
            where, C  is the leakage coefficient and it is proportional to pressure difference p
                   1
            across the piston and p is the pressure variation. The first term in Eq. (7.9) is the
            flow rate required to move the piston by the speed (sy).
              Eliminating the variables p, q, and x and with some algebraic manipulation, the
            overall transfer function becomes

                                            (a +b)
                                             a   
             y: =                                
                                 ⋅
                        ⋅
                                                              ⋅
                                        2
                    C M   (C M)   s       C      (C C)    b  
                                p
                                                                         s1
                b⋅     1    +    ⋅    +    C ⋅    +  A +  1   ⋅   ⋅+
                                                                     ⋅
                                                 p
                        A   A     K 1a ⋅        A  A     AK 1 
                                                                         (7.10)
            Equation (7.10) represents a second-order transfer function which was discussed
            in detail in previous chapters. The natural frequency which represents the speed of
            response is given by the coefficient of s  in the denominator and the damping ratio
                                            2
            is given by the coefficient of s in the denominator. As was discussed in the previous
            chapters, the important behavior of second-order transfer functions is stable but the
            damping ratio might become very small resulting in excessive oscillations. From
            the following equations, the natural frequency and damping ratio can be obtained.
   118   119   120   121   122   123   124   125   126   127   128