Page 9 - e-book Calculcs I

3
6
8. lim →+∞ √ + 5 −
3
3
lim →+∞ √ + 5 − = lim →+∞ √ (1 + 5 6 ) −
6
6
3
3
= lim →+∞ | |√1 + 5 6 −
3
3
= lim →+∞ √1 + 5 6 −
3
= lim →+∞ (√1 + 5 6 − 1)

= 0

2
√ −9
9.lim →3 + −3
2
−3
0
lim →3 + √ −9 = lim →3 + √ −9 =
2
0
−3
+
( ) > 0 ; → 3
2
lim →3 + √ −9 = +∞
−3

3
2−4
10. lim →0 − 5 +3 3
2
2
3
2−4
0
lim →0 − 5 +3 3 = lim →0 − 5 +3 3 = = 0
2
3
2
2−4
−
( ) > 0 ; → 0
3
2−4
lim →0 − 5 +3 3 = -∞
2

4
3
11. lim →−1 + √ −2 + 3
2
−8 −9
3 4 −8 −9 0
2
lim →−1 + √ −2 + 3 = lim →−1 + 3 4 = = 0
2
−8 −9
2
+
( ) > 0 ; → −1 √ −2 + 3
4
3
lim →−1 + √ −2 + 3 = -∞
2
−8 −9

9