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Persamaan reaksi :
CH3COOH(aq) + NaOH(aq) → CH3COONa(aq) + H2O(l)
Mula-mula = 10 mmol 5 mmol - -
Bereaksi = -5 mmol -5 mmol +5 mmol +5mmol
+
Setimbang = 5 mmol - 5 mmol 5 mmol
CH3COONa(aq) ⇌ CH3COO (aq) + Na +
-
5 mmol 5 mmol
+
[H ] = Ka x pH = - log [H ]
+
pH = - log 1,8 x 10 -5
H ] = Ka x CH COOH
+
3
CH COO − pH = 5 - log 1,8
3
= 1,8 x 10 -5 x 5 pH = 5 - 0,25
5
= 1,8 x 10 x 1 pH = 4,75
-5
= 1,8 x 10 -5
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