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        Persamaan reaksi :


                            CH3COOH(aq) + NaOH(aq) → CH3COONa(aq) + H2O(l)

        Mula-mula =          10 mmol               5 mmol                -                     -

        Bereaksi       =      -5 mmol              -5 mmol               +5 mmol               +5mmol


                                                                                                             +

        Setimbang =           5 mmol                       -              5 mmol               5 mmol





        CH3COONa(aq) ⇌ CH3COO (aq) + Na                  +
                                            -

        5 mmol                   5 mmol





                                                                           +
        [H ] = Ka x                                       pH = - log [H ]
            +
                                          
                                                          pH = - log 1,8 x 10      -5
        H ] = Ka x         CH COOH
           +
                               3
                           CH COO   −                     pH = 5 - log 1,8
                               3
               = 1,8 x 10   -5  x  5                      pH = 5 - 0,25
                                   5     
               = 1,8 x 10 x 1                             pH = 4,75
                            -5
               = 1,8 x 10    -5



































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