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Pengenceran larutan buffer
Pengenceran buffer asam
Ketika larutan CH COOH (pH = 4,74) diencerkan
3
dengan 9 L air
M x V
[CH COOH] =
3
V
total
0,1 x 1
[CH COOH] = 10 = 0,01 M
3
M x V
[CH COOH] =
3
V
total
0,1 x 1
[CH COOH] = 10 = 0,01 M
3
CH COOH
3
[H⁺] =
CH COO¯
3
0,01
[H⁺] = 1,8 10⁻⁵
0,01
[H⁺] = 1,8 10⁻⁵
pH = 5 – log 1,8 = 4,74
