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Pengenceran larutan buffer
Pengenceran buffer basa
Ketika larutan NH (pH = 9) diencerkan dengan 9
3
L air
M x V
[NH ] =
3
V
total
[NH ] = 0,1 x 1 = 0,01 M
3
10
M x V
[NH ] =
3
V
total
0,1 x 1
[NH ] = 10 = 0,01 M
3
NH 3
[OH⁻] =
NH4⁺
0,01
[OH⁻] = 1,0 10⁻⁵
0,01
[OH⁻] = 1,0 10⁻⁵
pOH = 5
pH = 14 – 5 = 9
