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PENGUJIAN BAHAN 2 (BETON ASPAL)

DATA HASIL PENGUJIAN:

P E R C O BA A N M A R S H A L L
SN I 06 - 2489 - 1991
SPESIFIK A SI T A N G G A L
A G REG A T D IK ERJA K A N
A SPA L D IPERIK SA
N o . a b c d e f g h i j k l m n o p q r
1
2
3
RA T A 2
1
2
3
RA T A 2
1
2
3
RA T A 2

G m m * : K a G mm : B j. agregat bulk : B j. agregat eff. : B j. aspal : A bs. A spal :

Keteran g an :
a = tin g g i b rik et ( m m ) h = b erat isi ( d / g ) j= % ron g g a th d . ag reg at 1 0 0 -( h * ( 1 0 0 - c))/ b j. b u lk ) p = k eleleh an ( m m )
b = % asp al terh ad ap ag reg at i = b erat jen is m ak sim u m ( teoritis) k = % ron g g a th d . cam p u ran 1 0 0 -( 1 0 0 x ( h / i) q = H asil b ag i M arsh all
c = % asp al terh ad ap cam p u ran 100 l = % ron g g a terisi asp al ( 1 0 0 x ( j- k ))/ j o / p ( k g / m m )
d = b erat k erin g ( g r) % ag reg at % asp al m = p em b acaan arloji stab ilitas r = Kad ar asp al eff. (% )

e = b erat d alam k ead aan jen u h ( g r) f BJ. ag reg at BJ. asp al n = stab ilitas ( m x k on v ersi) o c-(( Ab s. asp al/ 1 0 0 )* ( 1 0 0 - c))
g = isi ( e- f) = stab ilitas ( k g )
n x k orek si b en d a u ji
= b erat d alam air ( g r)

* G mm : d iten tu k an d en g an cara AAS H TO T 2 0 9 * * BJ. E ff Ag r = (1 0 0 - P b) * * * Ab sorp si asp al terh ad ap total ag reg at =
p ad a k ad ar asp al op tim u m p erk iraan ( P b ) ( 1 0 0 / G mm )-( P b/ BJ. asp al) ( BJ. E ff. ag r - BJ. Bu lk ag r) x BJ. Asp
1 0 0 x
P b = 0 , 0 3 5 (% CA)+ 0 , 0 4 5 (% FA)+ 0 , 1 8 (% FF)+ K ( BJ. E ff. ag r x BJ. Bu lk ag r)
K = 0 , 5 - 1 u n tu k L aston ; 2 - 3 u n tu k L ataston

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