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PENGUJIAN BAHAN 2 (BETON ASPAL)




 DATA HASIL PENGUJIAN:



 P E R C O BA A N M A R S H A L L
 SN I 06 - 2489 - 1991
 SPESIFIK A SI                                T A N G G A L
 A G REG A T                                  D IK ERJA K A N
 A SPA L                                      D IPERIK SA
 N o .   a   b   c   d   e   f   g   h   i   j   k   l   m   n   o    p         q         r
 1
 2
 3
 RA T A 2
 1
 2
 3
 RA T A 2
 1
 2
 3
 RA T A 2

 G  m m     *     :   K a G  mm   :   B j. agregat bulk  :   B j. agregat eff.   :   B j.  aspal   :   A bs. A spal   :

 Keteran g an   :
 a = tin g g i b rik et ( m m )   h = b erat isi ( d / g )   j=  %  ron g g a  th d .  ag reg at  1 0 0 -( h * ( 1 0 0 - c))/ b j. b u lk )   p = k eleleh an ( m m )
 b = %  asp al terh ad ap ag reg at   i = b erat jen is m ak sim u m ( teoritis)   k  =  %  ron g g a  th d .  cam p u ran  1 0 0 -( 1 0 0 x ( h / i)   q = H asil b ag i M arsh all
 c = % asp al terh ad ap cam p u ran   100    l = % ron g g a terisi asp al ( 1 0 0 x ( j- k ))/ j   o / p ( k g / m m )
 d = b erat k erin g ( g r)   % ag reg at   % asp al   m  = p em b acaan arloji stab ilitas   r = Kad ar asp al eff. (% )
 e = b erat d alam k ead aan jen u h ( g r) f   BJ. ag reg at   BJ. asp al        n = stab ilitas ( m x k on v ersi) o   c-(( Ab s. asp al/ 1 0 0 )* ( 1 0 0 - c))
         n x k orek si b en d a u ji
 g  = isi ( e- f)   = stab ilitas ( k g )
 =  b erat d alam air ( g r)


 *  G mm  :  d iten tu k an d en g an cara AAS H TO T 2 0 9   *  *  BJ. E ff Ag r      =     (1 0 0 - P  b)      *  * *  Ab sorp si  asp al  terh ad ap  total  ag reg at  =
 p ad a k ad ar asp al op tim u m p erk iraan ( P b )   ( 1 0 0 / G mm  )-( P  b/ BJ. asp al)   ( BJ. E ff. ag r - BJ. Bu lk ag r)   x  BJ. Asp
                                                  1 0 0 x
 P b  =  0 , 0 3 5 (% CA)+ 0 , 0 4 5 (% FA)+ 0 , 1 8 (% FF)+ K   ( BJ. E ff. ag r x BJ. Bu lk ag r)
 K = 0 , 5 - 1 u n tu k L aston ; 2 - 3 u n tu k L ataston






















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