Page 8 - KI - Física 4_Neat

Física 4° Secundaria

Resolución:
K = AB + CW
[K] = [AB + CW]

Sabemos que:
[x + y] = [x] = [y]

 [AB] = [CW]
[A][B] = [C][W]
−
1 −
2 3
ML T L

[A][ ] = [W]  [W] =
[C] MLT − 2
[w] = L

3. La ecuación mostrada es dimensionalmente correcta :
R= P v+ Q X
P =potencia
v = velocidad Q = calor
Determine La formula dimensional de RX

Resolución:
Por P. homogeneidad:
[A + B] = [A] = [B]

 [R] = [Pv] = [QX] …….()
[R] = [Pv]  [R] = [P][v]

-1
2 -3
 [R] = ML T LT
-4 3
[R] = MT L

De ()
[R]=[QX]
[R]=[Q][X]
3
ML T − 4
 [R] = [X]  [X] =
[Q] L T M
2
2
−

-2
[X]=LT
4
 [R][X]=L MT − 6

4. Obtener [x] si:
3e ( m + ) x 4
a =
t 2

Donde: a = Fuerza; m = Velocidad

Resolución:
Sabemos que:
[m + x] = [m] = [x]

 [x]=LT − 1

5. Determine la dimensión de x si:
2
E = W A − 2 X
Donde:
A = Calor;
W = Caudal

Resolución:
Por P. homogeneidad:
2
2
[A – x ] = [A ] = [x ]
2
2
 [A] = [x]

2
[x]=ML T − 2

er
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