Page 12 - Bahan Ajar Bismillah(2)

Penyelesaian

a. = − − 7
2
3
′
2
3
Misal: = − → = −3 3−1 = −3
′
1
= 7 → = 7.1. 2−1 = 7 = 7
′
2
′
Jadi jika = − , maka = − = −3 − 7
′
2
b. = 4 +15x
′
2
Misal: = 4 → = 4.2. 2−1 = 8
0
′
= 15 → = 15. 1−1 = 15. = 15
′
Jadi jika = + , maka = + = 8 + 15
′
′
3
c. = 9 − 3 + 5
2
2
′
3
Misal: = 9 → = 9.3. 3−1 = 27
′
′
= 3 → = 3. 1−1 = 3
′
′
= 5 = 5 −2 → = 5. −2 . −2−1 = −10 −3 = −10
2 −3
′
Jadi, jika = − + , maka = − +
′
′
′
10
2
′
= 27 − 3 −
−3
3
d. = 5 − + 1
2
0
′
Misal: = 5 → = 5. 1−1 = 5 = 5
2
2 2 −1 2 − 1 2
3
′
= = 3 → = 3 = 3 = 3
2
3 3 3
′
= 1 → = 0
′
′
Jadi, jika = − + , maka = − + ′
′
′
= 5 − 2
3
3

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