Page 7 - Bahan Ajar Bismillah(2)

c. = + 9
3
+ = ( + ) + 9
3
= + 3 +3 + + 9
2
3
3
2

′( ) = + h − ( )
lim
h→0 h
3
2
2
= + 3 +3 + + 9 − ( + 9)
3
3
lim
h→0 h
2
2
= 3 +3 + 3
lim
h→0 h
2
2
= (3 + 3 + )
lim
h→0 h
2
2
= lim(3 + 3 + )
h→0
2
2
= 3 + 3 . 0 + 0
= 3 + 0 + 0
2
2
= 3

3
d. =

+ = 3
+

′( ) = + h − ( )
lim
h→0 h
= 3 − 3
lim +
h→0 h
= 3 −3( + )
( + )
lim
h→0 h
= 3 − 3 − 3
lim
h→0 hx(x + h)

= −3
lim
h→0 hx(x + h)

3 | P a g e K E L A S X I