Page 13 - Bahan Ajar Berbasis Flipped Learning pada materi Diferensial

Penyelesaian

a. = (2 + 1)

Misal: = → = 1
′
= 2 + 1 → = 2
′
Jadi jika = . , maka ′ = ′ + ′

′
= 1. (2 + 1) + . 2
′
= 2 + 1 + 2
′
= 4 + 1 atau = 4 + 1

2
b. = 4(5 + 3)
2
′
Misal: = 4 → = 8
= 5 + 3 → = 5
′
Jadi jika = . , maka ′ = ′ + ′

′
= 8 . (5 + 3) + (4 ). 5
2
2
2
′
= 40 + 24 + 20
′
2
2
= 60 + 24 atau = 60 + 24

c. = (2 + 1)( − 4)
′
Misal: = 2 + 1 → = 2
′
= − 4 → = 1
Jadi jika = . , maka ′ = ′ + ′
′
= 2. ( − 4) + (2 + 1). 1
′
= 2 − 8 + 2 + 1
′
= 4 − 7 atau = 4 − 7

d. = ( − 5)(2 − 7)
2
Misal: = − 5 → = 2
′
2
′
= 2 − 7 → = 2
Jadi jika = . , maka ′ = ′ + ′

= 2 . (2 − 7) + 2. ( − 5)
′
2
2
′
= 4 − 14 + 2 − 10
2

12 | T u r u n a n K e l a s X I S M A