Page 49 - EBOOK ASAM BASA BERKONTEKS GREEN CHEMISTRY DAN SOCIO SCIENTIFIC ISSUES (SSI)
P. 49

Maka:

                          [H⁺][Se²⁻]
                Ka₂ =
                            [HSe⁻]

                               (0,0072 + x)(x)
               1,0 x 10⁻¹¹ =                      diasumsikan 0,0072 + x ≈ 0,0072 dan 0,0072 - x ≈ 0,0072
                                (0,0072 - x)

                                (0,0072)(x)
               1,0 x 10⁻¹¹ =
                                  (0,0072)

                x = 1,0 x 10⁻¹¹ M


                Sehingga,
                [H₂Se] = (0,40 - x) = (0,40 - 0,0072) = 0,39 M
                [HSe⁻] =  (0,0072 - x) = 0,0072 M atau 7,2 x 10⁻³ M
                [H⁺] = (0,0072 + x) = 0,0072 M atau 7,2 x 10⁻³ M
                [Se²⁻] = 1,0 x 10⁻¹¹ M
























































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