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2.1  Functional Group Characteristics and Roles          97



                    Functional group D: This is a heterocyclic aromatic ring. It is electron withdrawing due to induction.
                    This electron withdrawing property is responsible for the increased acidity of the adjacent sulfon-
                    amide (discussed in Chapter 3*).


                 3.  Shown below is the structure of imipramine as well as three analogs. Evaluate each analog and
                    provide an overall evaluation of how each change will affect the chemical properties of imipramine.










                                                   Imipramine
















                     Analog A                          Analog B                           Analog C



                    Answer

                    Analog A: In this analog, a chlorine atom has replaced a hydrogen atom. A hydrogen atom generally
                    does not contribute to electronic and solubility properties. Additionally, it is the smallest atom and
                    thus sterically occupies the least amount of space. In contrast, the chlorine atom is electron with-
                    drawing in character, enhances the overall lipid solubility of imipramine, and sterically is larger than
                    the original hydrogen atom.

                    Analog B: Similar to Analog A, this analog occurs via the replacement of a hydrogen atom with
                    another functional group. The alkyl chain (propyl chain) is electron donating, enhances the overall
                    lipid solubility of imipramine, and is sterically much larger than the original hydrogen atom.
                    Analog C: In this analog, a methyl group has been replaced by an acetyl group that converts the
                    tertiary amine to an amide. The methyl group is electron donating and contributes to the basicity
                    of the tertiary amine. In contrast, the carbonyl group is electron withdrawing. This significantly
                    decreases the availability of the lone pair of electrons on the nitrogen atom such that it is no longer
                    basic. In terms of solubility, the substitution of the acetyl group for the methyl group decreases water
                    solubility. This is because the nitrogen atom is no longer basic and thus cannot undergo ionization.
                    The resulting amide is water soluble due to its ability to act as a hydrogen bond acceptor; however,
                    the change from a functional group that can ionize to one that can only participate in hydrogen
                    bonding results in an overall decrease in water solubility. Finally, the acetyl group is sterically larger
                    than the original methyl group.



















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