Page 309 - Basic Electrical Engineering
P. 309

v = V  sin ωt
                                                                     m
                or,                                            v = 324.3 sin 314t

                Inductive reactance,                           X  = ωL = 314 × 0.5 = 15.7 Ω
                                                                 L


               Capacitive reactance,












               When the voltage is applied across a 25 Ω resistor, the current will be








               or,                    i = 12.97 sin 314t A


               Current through the inductor is














               or,                    i = 2.06 sin (314t − 90°)A



               Current through the capacitor is













               or,                    i = 10.07 sin (314t + 90°) A
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