Page 364 - Basic Electrical Engineering
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The phasor diagram representing the branch currents and the line current
with respect to the supply voltage has been shown in Fig. 3.53. The line
current lags the applied voltage by an angle, ϕ = 53 °.
Figure 3.53
Thus,
power factor = cos ϕ = cos 53°
= 0.6 lagging
It may be noted that the branch II is more resistive and less inductive than
branch I. That is why current I is more lagging than current I .
2
1
Power, P = VI cos ϕ
= 230 × 9.44 × cos 53°
= 230 × 9.44 × 0.6
= 1302.7 W
Example 3.24 Two impedances Z = 10 + j12 and Z = 12 – j10 are
1
2
connected in parallel across a 230 V, 50 HZ supply. Calculate the current,
power factor, and power consumed.
Solution:
