Page 361 - Basic Electrical Engineering

current in the inductive branch lags the voltage by 90°. The phasor sum of the
branch currents gives us the total line current. Since in a parallel circuit
voltage, V is common to the parallel branches, we generally take V as the

reference axis while drawing the phasor diagram. Current through the
resistive branch, I has been drawn in phase with V. Current through the
R
inductive branch, I is lagging V by 90°. The sum of I and I gives I as has
R
L
L
been shown in Fig. 3.51.

Power factor,

Figure 3.51

Now using the given values, calculations are made as follows.

Inductive reactance,

X = ωL = 2πfL
L
−3
= 2 × 3.14 × 50 × 100 × 10 Ω
= 31.4 Ω