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Optical Modulators and Modulation Schemes                                          149


                                     0      1      0      1      1      1
                                +1
                             b(t)                                                 t
                                  0       T b    2T b   3T b   4T b   5T b   6T b
                                –1
                                +1
                         m(t – T )                                                t
                              b
                                –1
                                +1

                            m(t)                                                  t
                                –1

                               Figure 4.11  Input waveform b(t) and message waveform m(t).


           Example 4.1

           Consider the input data sequence
                                              {b }= 01101110.
                                                n
           To proceed with the deferential encoding, add an extra bit to the encoder output. This extra bit may be chosen
           arbitrarily to be 0. Determine the encoded message sequence m .
                                                             n
           Solution:
           Let the first bit of the sequence m be0(or −1 V), which serves as the reference. To transmit the first bit
                                      n
           0of {b }, we introduce no phase shift relative to the reference voltage. Therefore, the voltage level of the
                n
           second bit of {m } is −1 V (or 0). To transmit the second bit 1 of {b }, we introduce a  phase shift relative
                                                                 n
                        n
           to the reference voltage (the voltage corresponding to the second bit of {m }). Therefore, the voltage level
                                                                       n
           corresponding to the third bit of {m } is +1 V (or 1). Continuing this process, we find
                                       n
                                              {m }= 001001011.
                                                n

           4.6  Optical Modulators

           The simplest optical modulator we could think of is the switch of a flash light. Suppose we turn on a flash
           light for 1 second and turn it off for 1 second. We generate digital data ‘1’ and ‘0’, respectively, as shown in
           Fig. 4.12. In this example, the bit rate of the optical data generated from the flash light is 1 bit/s.
            Optical modulation techniques can be divided into two types: (i) direct modulation of lasers and (ii) external
           modulation of lasers.


           4.6.1  Direct Modulation

           The laser drive current can be modulated by a message signal, as shown in Fig. 4.13. For example, when the
           message signal is bit ‘0’ (bit ‘1’), the laser is turned off (on) and, therefore, the information in the electrical
           domain is encoded onto the optical domain. Directly modulated lasers (DMLs) have some major drawbacks.
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