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Optical Amplifiers                                                                 271


            The reflectivity of the AR coating is quite sensitive to the width  and refractive index n of the AR coating.
                                                                                 2
           To increase the tolerance, a multilayer AR coating can be used. The experimental results of Ref. [8] show that
           the tolerances in  and n of a single-layer AR coating for realizing the power reflectivity R ≤ 1 × 10 −3  are
                               2
                   ∘                                                                  ∘
           about ±60 A and ±0.05, respectively. The double-layer AR coating has larger tolerances, ±90 A in widths
           and ±0.3 in refractive index, for the same power reflectivity as in the single-layer AR coating. In this section,
           we have assumed that the optical field is a plane wave and as a result, we obtained a simple expression for
           the width of the AR coating. However, in a waveguide, plane waves should be replaced by the modes of the
           waveguide and the reflectivity should be calculated [8].



           6.6.4  Gain Saturation
           As the input signal power increases beyond a certain threshold, the gain G decreases for both cavity-type
           FPA and TWA. This is known as gain saturation. This phenomenon can be explained as follows. When the
           population inversion is achieved, the stimulated emission dominates the absorption. Since the stimulated
           emission rate is proportional to photon density, a larger input signal power enhances the stimulated emission
           and, therefore, the excited carriers are depleted and the gain decreases. Under steady-state conditions, we can
           set dN ∕dt to zero in Eq. (3.123) to obtain
                e
                                                          N e   I
                                         G (N − N )N +       =   ,                         (6.139)
                                           0  e   e,0  ph
                                                             qV
                                                           e
           where
                                                 G =Γ .                                (6.140)
                                                  0     g
           Simplifying Eq. (6.139), we find
                                                I∕qV + G N N
                                                        0 e,0 ph
                                            N =                ,                           (6.141)
                                             e
                                                  G N + 1∕ e
                                                    0 ph
                                                     (I∕qV − N ∕ ) 
                                                              e,0
                                                                 e
                                                                    e g
                                    g =  (N − N )=                   .                   (6.142)
                                         g  e   e,0
                                                         G N  + 1
                                                          0 ph e
           Eq. (6.142) can be rewritten as
                                                      Γg 0
                                             Γg =             ,                            (6.143)
                                                  1 + N ∕N ph,sat
                                                      ph
           where
                                            g =(I∕qV − N ∕ )  ,                      (6.144)
                                             0
                                                         e,0
                                                            e
                                                               g e
                                                   1
                                         N    =       .                                    (6.145)
                                           ph,sat
                                                Γ 
                                                   g  e
           The optical power P and photon density N ph  are related by (Eq. (3.136))
                                               P = N ℏ A.                              (6.146)
                                                    ph
                                                        0
           So, Eq. (6.143) may be rewritten in terms of P as
                                                      Γg 0
                                               Γg =         ,                              (6.147)
                                                    1 + P∕P
                                                          sat
                                                    ℏ A
                                                      0
                                              P sat  =   .                                 (6.148)
                                                    Γ 
                                                      g e
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