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Nonlinear Effects in Fibers                                                        487



           Example 10.12
           The evolution of the complex field envelope in a periodically amplified fiber-optic system is governed by
                                                               N
                                    2
                         q   (Z)  q     2      (Z)    ∑
                               2
                        i   −          + (Z)|q| q =−i  q + iA  (Z − nL )q(T, nL ),    (10.471)
                                                                               a−
                                                                        a
                         Z    2  T 2              2
                                                              n=1
           where
                                       (Z)=   for 0 < mod(Z, L ) < L
                                       2      20               a    a
                                           = 0    otherwise,                              (10.472)
                                       (Z)=   for 0 < mod(Z, L ) < L
                                              0                a    a
                                           = 0    otherwise                               (10.473)

                                       (Z)=   for 0 < mod(Z, L ) < L
                                              0                a    a
                                           = 0    otherwise                               (10.474)
           Using the transformation

                                            q(Z, T)= a(Z)u(Z, T),                         (10.475)
           show that
                                                  2
                                       u   (Z)  u    2  2
                                             2
                                      i   −          + a (Z)|u| u = 0,                    (10.476)
                                       Z    2  T 2  2
                                     a(Z)= e − 0 Z∕2  for 0 < mod(Z, L ) < L a
                                                                 a
                                         = 1    otherwise.                                (10.477)

           Assume that the fiber loss is exactly compensated by the amplifier gain.

           Solution:
           Consider the propagation over a short length from nL a−  to nL a−  +ΔZ corresponding to the amplifier located
           at nL . In this short length,  (Z)= (Z)= (Z)= 0. Integrating Eq. (10.471) from nL a−  to nL a−  +ΔZ,we
               a
                                  2
           obtain
                                  nL a− +ΔZ         nL a− +ΔZ
                                         dq
                               i           dZ = iA        (Z − nL )q(T, nL ),           (10.478)
                                ∫       dZ        ∫
                                                                  a
                                                                         a−
                                 nL a−             nL a−
                                   q(T, nL  +ΔZ)− q(T, nL )= Aq(T, nL ),                  (10.479)
                                         a−             a−          a−
                                           q(T, nL  +ΔZ)
                                                 a−
                                                         = A + 1.                         (10.480)
                                             q(T, nL )
                                                   a−
           Since q(T, nL a−  +ΔZ) and q(T, nL ) represent the amplifier output and input, respectively, we have
                                       a−
                                                       √
                                       q(T, nL a−  +ΔZ)=  Gq(T, nL ),                     (10.481)
                                                                a−
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