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Nonlinear Effects in Fibers                                                        489



                               a(z)
                                  1

                                                           G




                                                                           z
                                             L a       2L a  nL a
                                      Figure 10.33  Plot of a(Z) vs. distance Z.






           Example 10.13
                                              2
           Show that the Fourier transformation of |u | u is
                                            0   0
                                         P 3∕2 3 √    ∑
                                            T
                                             0
                                          0
                                                                         2
                                  2
                             {|u | u }=              b b b exp [g +(i − d) ∕4C],
                                 0
                                    0
                                                       l m n
                                        |T | T   C
                                            2
                                          1   1    lmn
           where
                                         √       ∞       [           ]
                                           P T  ∑           (T − nT ) 2
                                            0 0
                                                                  s
                                     u =            b exp −           ,
                                      0
                                                     n
                                           T 1  n=−∞           2T 1 2
                                                      2
                                                    3T + iS
                                                      0
                                               C =    4     ,
                                                          2
                                                   2(T + S )
                                                      0
                                                     2
                                          [(l + m + n)T + i(l + m − n)S]T s
                                                    0
                                      d =                            ,
                                                     4
                                                    T + S 2
                                                     0
                                              2
                                         2
                                                             2
                                                         2
                                                                 2
                                                  2
                                                    2
                                       [(l + m + n )T +(l + m − n )iS]T 2 s
                                                    0
                                    g =                                .
                                                      4
                                                   2(T + S )
                                                          2
                                                      0
           Solution:
           Let                                     [          ]
                                                     (T − lT ) 2
                                                           s
                                            r = exp −          ,                          (10.491)
                                            l
                                                        2T 2
                                                          1
                                                              ∞
                                                                       ∞
                                                      ∞
                                                  T
                                               P 3∕2 3  ∑    ∑        ∑
                                                0
                                                   0
                                           ∗
                                 2
                              |u | u = u u u =           b r     b r      b r ∗
                                                                           n n
                                                          l l
                                                                  m m
                                   0
                                0
                                       0 0 0
                                                  2
                                              |T | T
                                                1   1 l=−∞  m=−∞     n=−∞
                                       P 3∕2 3
                                          T ∑
                                           0
                                        0
                                                         ∗
                                    =           b b b r r r ,                             (10.492)
                                                 l m n l m n
                                          2
                                      |T | T
                                        1   1 lmn
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