Page 252 - BA2 Integrated Workbook - Student 2017
P. 252

Fundamentals of Management Accounting




               2.3 D

                     Options B and C would begin from 0 and are clearly incorrect. Option A would
                     be similar to the graph given except it would be flat at the top due to the
                     maximum annual charge.


               2.4 A


                     The preparation, mixing and tinning departments are all cost centres. The soup
                     is not poured into tins until the tinning department so a 400g tin of soup would
                     not be a suitable cost unit for the mixing department.



               CHAPTER 3 – ANALYSING AND PREDICTING COSTS


               3.1 C

                                           Calls       Cost
                     Highest month         900        $4,000
                     Lowest month          400        $2,000
                                           ––––      ––––––

                     difference            500        $2,000

                     Variable cost per unit = ($2,000 ÷ 500) = $4.

                     Using 400 units: Fixed cost = $2,000 - ($4 × 400) = $400.


               3.2  b = 8.516

                                  n∑xy – (∑x)(∑y)             (10 × 1,457.5) – (23 × 600)
                      b =          ————–——–—    =             ————————————  = 8.516
                                                  2
                                         2
                                     n∑x – (∑x)                      (10 ×62) − 23 2
               3.3  r = 0.83
                                         n∑xy – (∑x)(∑y)
                     r =      —–———————————
                                     2
                                                           2
                                            2
                                                   2
                             √( n∑x – (∑x) )(n∑y  –(∑y) )

                                          (10 × 1,457.5) – (23 × 600)
                     r =       ———————————————————                               = 0.83
                                                                             2
                                                   2

                                  √[( 10 × 62) – 23 ][(10 × 363,9500) –600 ]







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