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168 Data Sufficiency
So, by Using Statement I alone, we can say that E D
sits on the immediate right of A.
F North-west North
13. (d) Even by using both the statements, we are not
able to determine who is tallest as we do not have S
the exact idea about the height of Q. From I and II:
14. (b) From I: EAST or ETSA F North-west
Hence I alone is not sufficient D
From II: Only EAST is possible
E
Hence II alone is sufficient. S
15. (a) From I Point E is to the north-west of Point S.
C (–)
D (+) – M’s father (+) 18. (b) From I: Possible months: January, February,
March, April, May or June.
M From II: Rahul’s son correctly remembers that his
Hence C is the grandmother of M. father went on vacation after 31 March but before
st
From II: 1 May. So his father went on vacation in the month
st
C of april. Hence only II is sufficient.
19. (c) From I: The possible day of exam is Wednesday.
E(–) ⇔ – F (–) From II: The third day of the week is Wednesday.
S (–) – M Hence, either statement I alone or statement II alone
is sufficient.
We still don’t know C’s sex. 20. (d) From I: Two-digit marks is less than or equal to
16. (e) From I: P > Q, but T is not the tallest. 20.
From II: R > P, but S is not the tallest. Possible marks: 10, 11, 12, 13, 14, 15, 16, 17, 18,
From I and II: R > P > Q. Neither S nor T can be the 19 and 20.
tallest. Hence R is the tallest. From II: Suman scored more than 9 marks.
17. (e) From I: Possible marks: 10, 11, 12, 13, 14, 15, 16, 17, 18,
N 19 and 20.
F Hence statement I and II together are not sufficient.
W E
E D
S
From II:
Concept Deviator
1. (d) If we look at Statement I then we will get Now by using statements I and II together
If a = 3 and b = 2, a + b > 0. Here b > 0 If a = 3 and b = 2, a – b > 0 and a + b > 0. Here
If a = 3 and b = – 2, a + b > 0. Here b < 0 b > 0
Hence I alone is not sufficient. If a = 3 and b = –2, a – b > 0. and a + b >0. Here
Now if we look at Statement II only then we will get b < 0.
Hence I and II together are also insufficient.
If a = 3 and b = 2, a – b > 0. Here b > 0
If a = 3 and b = – 2, a – b > 0. Here b < 0 2. (c) If we look at Statement I
i = p – 17 and r = p – 103
Hence II alone is not sufficient.