Page 41 - Lösung Merkheft
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3. 1. DER ZYLINDER – OBERFLÄCHE
A=Π•r²
2 Π • r
h A=2 Π • r • h = M h
2 Π • r
A=Π•r²
O = 2• +
O = 2Π•r²+2Πr h
M = 2 Π • r • h
O=2Πr(r+h)
r= 5 cm; h= 7cm →O=?; M=? M= 330 m²; r= 6,7 m → O=?; h=?
M = 2πr ∙ h M = 2πr ∙ h |: 2πr
M = 2π ∙ 5 ∙ 7 h = 330: (2π ∙ 5)
M = 219,91 cm² h = 7,83 m
O = M + 2πr² O = M + 2πr²
O = 219,91 + 2π ∙ 5 O = 330 + 2π ∙ 6,7²
O = 219,91 + 157,08 O = 330 + 282,05
O = 376,99 cm² O = 612,05 m²
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