Page 12 - Modul Baru Turunan Trigonometri

Contoh 1:

Tentukan rumus turunan dari fungsi berikut.

1. ( ) = 5 sin

2. ( ) = 2 cos 3

3. ( ) = 3 sin 2 − cos 5

Jawab :

′
1. ( ) = sin → ( ) = cos
′
maka ( ) = 5 sin → ( ) = 5 cos
′
2. ( ) = cos → ( ) = − sin b
′
( ) = cos 3 → ( ) = −3 sin 3

′
maka ( ) = 2 cos 3 → ( ) = 2 (−3 sin 3 )
= −6 sin 3

3. ( ) = 3 sin 2 − cos 5

Pilih = 3 sin 2  ′ = 6 cos 2

= cos 5  = −5 sin 5
′
( ) = 3 sin 2 − cos 5 = −

′
′
maka ( ) = − ′
′
( ) = 6 cos 2 − (− 5 sin 5 )

= 6 cos 2 + 5 sin 5

Contoh 2:

Jika ( ) = sin + cos + tan maka (0) = ⋯
′
Jawab:

( ) = sin + cos + tan

2
′( ) = cos − sin + sec
2
′(0) = cos 0 − sin 0 + sec 0
= 1 − 0 + 1 = 2

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