Page 272 - Теория кавитации

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3.6 Making time for immediate calculations

We define the remaining attributes of cavitation ci1 f, ci1 e. Period Θ= 1/υ sec, where
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14
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υ is the photon frequency: υ= 6·10 Hz, i.e. Θ= 1/(6·10 ) = 1,7·10 sec; The value of
the gyroscopic frequency (in a field of a constant magnetic field) for an electron: ω=
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2
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m·c /h = 9,1·10 ·9·10 /(6,62·10 ) = 12,4·10 19 Hz , the period value is Θ=
19
1/(12,4·10 ) = 8·10 -21 seconds. If the magnetic field is stretched, then the angular
frequency is determined by the formula ω= e·B/m, and the resonant frequency is
determined by the formula υ= ω/(2·π), for example, B= 0.01 T (Tesla), υ= ω/(2·π)
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=e·B/(2·π·m) = 10 ·1,6·10 /(2·π·9,1·10 ) = 2,8·10 8 Hz, that is, the period Θ=
-2
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-9
1/(2,8·10 )=3,6·10 sec.
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What do these calculations show? As we have said, although the EP (which is either
a photon or an electron, as we agreed in advance for this work), which was transformed
into a cavitation ci1, is not a wave of classical physics, it is clear that the superhigh-
frequency HF-POM is a vibrational process. That is why we pay attention to the concept
of the period.
During each period, Θ the cavition has time to recover from the previous
microexplosion and, in the same time interval, the cavition has time to collapse once
again. Consequently, the period Θ is approximately divided into two halves Θ/2, on one
of them the cavitation is restored, and on the other half the cavitation collapses, thus
completing one full cycle of the oscillatory - vibration process. At the same time, the
energy of the microexplosion of the second stage is expended on the restoration of the
first stage bubble.

Here we would like to draw attention to the problem expressing the “spin of the
electron”: the fact that the period is divided into a hit would be interpreted as ½-spin.
After this period, it is easy to determine the duration of a pair of collapse-restoration of
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a cavition of type ci1: a photon for each period overcomes Θ·c ≈1,7·10 ·3·10 =
10
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5,1·10 m. For example, the distance from the Sun to the land is 14.96·10 m, i.e.
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2
17
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10
Θ·(14,96·10 /(5,1·10 )) ≈ 1,7·10 ·2,9·10 сек = 4,93·10 сек = 493 сек ≈ 8,2 min.
This means that a solar photon moving in the form of a cavition will reach the Earth
in 8.2 minutes.
Let us give an example for an electron: its velocity is v= 10 m/s (this is the thermal
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velocity of the electron v T, corresponding to the temperature T= 300 °K); this electron-
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5
cavitation overcomes the distance during the period Θ·v= 3,6·10 ·v = (3,6·10 sec)·(10
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m/sec) = 3,6·10 m; for example, to reach the end point of a conductor extending over
-4
-9
6
-4
6
a distance of 1000 km, Θ·(10 /(3,6·10 )) = 3,6·10 ·10 /(3,6·10 ) = 10 seconds, the
electron will spend 10 seconds, moving in the form of movement of the HF-POM.

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