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170                                                                Chapter 4

        energy. Simultaneously, through Maxwell’s equations (4.1) it is coupled to the magnetic field
        and its energy too. Evidently, the same is right for the scalar potential. However, it does not
        change the significant fact that both potentials are associated to EM energy concentrated into
        electric and magnetic fields. As we will demonstrate later, both potentials describe the wave
        propagating in space-time domain meaning they describe the transfer EM energy in space and
        time.
        More detailed discussion of the vector and scalar potentials and their physical significance is
        beyond the classical electrodynamics and the scope of this book. The readers can find more
        information attending [1 - 3]. In engineering practice, both potentials can be considered as a
        very useful tool simplifying the analysis of electromagnetic waves generated by the sources.

        4.1.5   Symmetry of Maxwell’s Equations and Principle of Duality. Electrodynamic
        Potentials for Magnetic Sources

        Although so far the magnetic charges and currents were nor observed, their introduction is very
        useful engineering tool since the magnetic current magnitude is measured in Volts (see (1.10)).
        As we have pointed out in Chapter 1, it will be perfectly valid without any mystics to interpret
        some voltage sources of electromagnetic fields and field sensors as magnetic charges, dipoles,
        and currents if the fields created by them and equivalent magnetic sources are identical. A tiny
        loop with electric current as a magnetic dipole is exemplary.

        Now suppose that we have gotten some solution of equation (4.22) with the given electric
        current source. It is natural to ask how we can transform this solution if the source is magnetic
        current. The elegant way to do so is the formal replacements of letters in the gotten solution
        (principle of duality)

                            ⟹ ,  ⟹ −,  Σ  ⟹  Σ ,   Σ  ⟹  Σ,    ⟺       (4.25)
                                                                   0 
                                                            
        As  the  following diagram  demonstrates, Maxwell’s equations and Lorentz’s  gauge (4.21)
        (check please) are invariant under this transformation  while electric source is replaced by
        magnetic one

                                                     
                       ×  = −     ×  =  
                                                           
                                0 
                                     ⎫  ⎧            
                                   ⎪   ⎪              
                       ×  =    +  ⎪  ⎪  ×  = −   −  Σ
                               
                                                           0 
                                      Σ
                                                      
                                            ⇒                                    (4.26)
                       ∘  =  ⁄        ⎬  ⎨   ∘  =  Σ ⁄  
                                                              0 
                                  
                              Σ
                      ∘  = 0          ⎪  ⎪   ∘  = 0
                              Σ  ⎪  ⎪          Σ
                       ∘  Σ  +  = 0     ⎭  ⎩   ∘  Σ  +  = 0
                                                   
        Therefore, we can acquire the new set of solutions of Maxwell’s equations
                                       = −(1   ) ×         (4.27)
                                             ⁄
                                                  
        solving the wave equations of exact the same type as (4.22) and (4.23)
                                    2
                           2      1        
                          ∇  −      −     = −  
                                                          
                                            
                             
                                   2    2    �              (4.28)
                                      2              
                             2
                                   1   
                            ∇  −     −    = −  
                               
                                              
                                    2    2     0  
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