Page 33 - ANALISIS VEKTOR (E-MODUL)

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Penyelesaian

Diketahui : W = ∫ +

Ditanya : w = ⋯ ? , w = ⋯ ? , w = ⋯ ?
b
c
a
Jawaban :
Langkah pertama mencari w
a

∗

y = m + c y = m + c
(0,0) →(1,2)
2 = m∙ (1) + c y = 2x
y = m + c
m = 2 dy = 2
0 = m-0+ c

c = 0



W a  xy dx  xdy
1

2
W a   2 dx  2xdx
x
0
2
W  x 3  x 2 1
a
3 0
2
W  ) 1 ( 3  ) 2 ( 2
a
3
5
W 
a
3
Langkah pertama mencari w
b

∗ w ,, = (0,2) → (1,2) y = m + c
b

(0,0) →(0,2) → (1,2) y = m + c y = 0- +2

,
w = (0,0) → (0,2) 2 = m-0+ c y = 2
b

x = 0 c = 2 dy = 0

dx =0