Page 28 - Nature Of Space And Time
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t = t
                                                                                2
                                                          period
                                                          t = 8pM



                                                                                  t = t
                                                                                     1
                                                     r=2M




                                                            r = constant



               imaginary time coordinate with period     2   .

                    So what is the signi cance of having imaginary time identi ed with some period  .

               To see this consider the amplitude to go from some  eld con guration   1 on the surface
               t 1 to a con guration   2 on the surface t 2. This will be given by the matrix element of
               e iH(t 2 −t 1 ) . However, one can also represent this amplitude as a path integral over all  elds
                 between t 1 and t 2 which agree with the given  elds   1 and   2 on the two surfaces.




                                                                              f= f 2 ;t = t 2












                                                                              f= f 1 ;t = t 1



                                  <  2;t 2 |   1;t 1 > = <  2 | exp(−iH(t 2 − t 1)) |   1 >

                                                         Z
                                                      =     D[ ]exp(iI[ ])




                    One now chooses the time separation (t 2 − t 1) to be pure imaginary and equal to  .
               One also puts the initial  eld   1 equal to the  nal  eld   2 and sums over a complete basis

               of states   n. On the left one has the expectation value of e   − H  summed over all states.
               This is just the thermodynamic partition function Z at the temperature T =         −1 .
                    On the right hand of the equation one has a path integral. One puts   1 =   2 and


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