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MANSOURA NATIONAL UNIVERSIY
PHARM D- CLINICAL PHARMACY LEVEL I PHARM. ANAL. CHEM. I (PC 101)
Concentration:
2E.P 1 x F x 1000
Concn. of Na 2CO 3 = = .......... g/L
10
For NaHCO 3 :
NaHCO 3 + HCl → NaCl + CO 2 + H 2O
1 HCl ≡ 1 NaHCO 3
standard sample
Equivalence factor (F):
1 x M.W. of NaHCO 3 x 0.2
each ml of 0.2 N HCl ≡ ≡ .......... g NaHCO 3
1 x 1000
Concentration:
(E.P 2 - 2E.P 1) x F x 1000
Concn. of NaHCO 3 = = .......... g/L
10
Results:
E.P 1 =
E.P 2 =
Concn. of Na 2CO 3 =
Concn. of NaHCO 3 =
Explanation
Demonstration
of the
experiment
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