Page 45 - PC 101 Interactive practical book

MANSOURA NATIONAL UNIVERSIY
PHARM D- CLINICAL PHARMACY LEVEL I PHARM. ANAL. CHEM. I (PC 101)

For Na 2CO 3 :

Na 2CO 3 + 2HCl → 2NaCl + CO 2 + H 2O

 2 HCl ≡ 1 Na 2CO 3

standard sample

1
 1 HCl ≡ Na 2CO 3
2
standard sample
Equivalence factor (F):

1 x M.W. of Na 2CO 3 x 0.2

each ml of 0.2 N HCl ≡ 2 ≡ .......... g Na 2CO 3
1 x 1000

Concentration:

2(E.P 2 - E.P 1) x F x 1000
Concn. of Na 2CO 3 = = .......... g/L
10
Results:

E.P 1 =

E.P 2 =

Concn. of NaOH =

Concn. of Na 2CO 3 =

Explanation

Demonstration

of the

experiment

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