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MANSOURA NATIONAL UNIVERSIY
PHARM D- CLINICAL PHARMACY LEVEL I PHARM. ANAL. CHEM. I (PC 101)
Exp.: Determination of HCl & CH3COOH mixture
P Pr ri in nc ci ip pl le e : :
According to the two-indicators method:
a) First step: (E.P M.O.) for HCl only
Titration of 10 ml of the mixture ≠ standard NaOH using M.O. indicator.
E.P M.O. ≡ HCl only
b) Second step: (E.P ph.ph.) for Total (HCl & CH3COOH)
Titration of another 10 ml of the mixture ≠ standard NaOH using ph.ph. ind.
E.P ph.ph. ≡ HCl + CH 3COOH
Reaction equations:
HCl + NaOH → NaCl + H 2O
CH 3COOH + NaOH → CH 3COONa + H 2O
Notes:
1) During the determination of HCl only (1 E.P. using M.O.):
st
NaOH neutralizes HCl only without interference of acetic acid because the
+
hydrogen ion (H ) of HCl suppresses the ionization of acetic acid by
common-ion effect as shown in the following equations:
HCl H + Cl
-
+
-
+
CH 3COOH H + CH 3COO
and when the neutralization of HCl is completed, the pH of the solution
reaches the pH-range of M.O. and so M.O. changes its color.
nd
While during the detn. of total HCl & acetic acid (2 E.P. using ph.ph.):
NaOH neutralizes HCl first without any change in the color of ph.ph. and
then the titration is completed to make neutralization of acetic acid also.
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